2x^2-7x+40=0

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Solution for 2x^2-7x+40=0 equation:


Simplifying
2x2 + -7x + 40 = 0

Reorder the terms:
40 + -7x + 2x2 = 0

Solving
40 + -7x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
20 + -3.5x + x2 = 0

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + -3.5x + -20 + x2 = 0 + -20

Reorder the terms:
20 + -20 + -3.5x + x2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -3.5x + x2 = 0 + -20
-3.5x + x2 = 0 + -20

Combine like terms: 0 + -20 = -20
-3.5x + x2 = -20

The x term is -3.5x.  Take half its coefficient (-1.75).
Square it (3.0625) and add it to both sides.

Add '3.0625' to each side of the equation.
-3.5x + 3.0625 + x2 = -20 + 3.0625

Reorder the terms:
3.0625 + -3.5x + x2 = -20 + 3.0625

Combine like terms: -20 + 3.0625 = -16.9375
3.0625 + -3.5x + x2 = -16.9375

Factor a perfect square on the left side:
(x + -1.75)(x + -1.75) = -16.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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